Finding PI using MPI collective operations

program main

      include 'mpif.h'

      double precision  PI25DT
      parameter        (PI25DT = 3.141592653589793238462643d0)

      double precision  mypi, pi, h, sum, x, f, a
      integer n, myid, numprocs, i, rc

      MPI_Init( ierr )
      MPI_COMM_RANK ( MPI_COMM_WORLD, myid, ierr )
      MPI_COMM_SIZE( MPI_COMM_WORLD, numprocs, ierr )

      print *, 'Process ', myid, ' of ', numprocs, ' is alive'

      sizetype   = 1
      sumtype    = 2
      
 10   if ( myid .eq. 0 ) then
         write(6,98)
 98      format('Enter the number of intervals: (0 quits)')
         read(5,99) n
 99      format(i10)
      endif
      
      call  MPI_BCAST(n,1,MPI_INTEGER,0,MPI_COMM_WORLD,ierr)

      if ( n .le. 0 ) goto 30

      h = 1.0d0/n
      sum  = 0.0d0
      do 20 i = myid+1, n, numprocs
         x = h * (dble(i) - 0.5d0)
         sum = sum + 4.d0 / (1.d0 +x*x)
 20   continue
      mypi = h * sum

      call MPI_REDUCE(mypi,pi,1,MPI_DOUBLE_PRECISION,MPI_SUM,0,
     $     MPI_COMM_WORLD,ierr)

      if (myid .eq. 0) then
         write(6, 97) pi, abs(pi - PI25DT)
 97      format('  pi is approximately: ', F18.16,
     +          '  Error is: ', F18.16)
      endif

      goto 10

 30   call  MPI_FINALIZE(rc)
      stop
      end